I throw two dice simultaneously.
What is the probability of getting sum as 9 of the two numbers shown ?
1/12
Possible cases = 6*6 = 36
Desired cases = [(3,6), (4,5), (6,3), (5,4)] = 4
=> 4/36 = 1/12
I throw two dice simultaneously.
What is the probability of getting sum as 9 of the two numbers shown ?
1/12
Possible cases = 6*6 = 36
Desired cases = [(3,6), (4,5), (6,3), (5,4)] = 4
=> 4/36 = 1/12
