In a basket of apples,
when counted in twos, there was one extra
when counted in threes, there were two extra when counted in fours, there were three extra
when counted in fives, there were four extra
when counted in sixes, there were five extra.
However, if the apples were counted in sevens, no extra apple was left. Can you calculate the minimum number of apples that were present in the basket ?
119
Let the number of apples = X
X / 2 => Remainder = 1
X / 3 => Remainder = 2
X / 4 => Remainder = 3
X / 5 => Remainder = 4
X / 6 => Remainder = 5
X / 7 => Remainder = 0
Therefore, X is divisible by 7.
Whenever X is divided by any number less than 7, the remainder is 1 less than the divisor.
=> X + 1 is the LCM of 2, 3, 4, 5 and 6.
Now LCM of 2, 3, 4, 5 and 6 = 60
But 60 - 1 = 59 is not divisible by 7
60 * 2 = 120
120 - 1 = 119 which is divisible by 7
This means that X + 1 = 120 or X = 119
Number of minimum number of apples in the basket = 119
