#441 - Cut The Swiss Cross Puzzle

Here is a Swiss Cross. You have to make two straight cuts in the figure so that it is divided into four congruent pieces. Also you should be able to join these pieces into a square then.Can you accept this challenge?

Cut The Swiss Cross Puzzle

You surely would not have thought that this could be that simple. It is like you are just trashing this image after thinking so much. But yeah that's how you have to do it.

#442 - Lateral Thinking Picture Puzzle

Assume the given figure to be a delicious doughnut. Yes, now you can concentrate more on the puzzle. So you have this delicious doughnut in your refrigerator when your friends come knocking at the door. There are eight of them. Now you have to make three cuts in this doughnut so that each one of you nine people can enjoy a piece of it. Neither you nor your friends would mind the size of their piece as long as they are getting it.How will you do it?

Lateral Thinking Picture Puzzle

This is one of the solution how you can do it. There is another way to do it. Run the horses of your mind and find out yourself.

#443 - which alphabet replaces the question mar

If we tell you that there is a relation between the numbers and letters in the given figure, can you analyze it and find the missing letter in the last box ?

which alphabet replaces the question mar

The missing letter in the last box is Z.

Denote each alphabet to the corresponding number. For example, A = 1, B = 2, C = 3 and so on. Now you will find that the center digit is actually the product of the alphabets on both sides. In such case, the missing letter is Z.

=>G(7) * Z(26) = 182

#444 - Hard Logic Sequence Puzzle

Complete the following series:

1, 4, 5, 6, 7, 9, 11, __?

Hard Logic Sequence Puzzle

100 will be the next number.

aJust check the spelling of every number. It does not contain the letter T. Thus the next number will be Hundred.

#445 - Easy Movie Rebus Riddle

Identify the movie name ?

Easy Movie Rebus Riddle

Pirates of Caribbean

#446 - Tricking Question

A ship is sailing in the water. It has a rope ladder hanging over its side. The rungs are 355 mm apart. Suppose if the water is rising one meter every 12 hours, how many rungs will be underwater after one day ?

Tricking Question

It does not matter how much apart are the rungs as no matter at how much speed the water level rises, none of the rungs will go underwater. This is because with the water level rising, even the ship will be rising. Thus none of the rungs go underwater.

#447 - Matchstick Problem

As you can see that fifteen matches have been used to form an arrangement. What you have to do is remove any six of them to make them ten.Can you do that?

Matchstick Problem

Look at the image and see how we did it.

#448 - which letter replaces the question mark

The below given figure comprises of a pattern through which you can determine the missing letter. Can you push your mind to find the pattern and add the missing letter?

which letter replaces the question mark

The missing letter is Q.

If you add the three numbers on each square, the value corresponds to the equivalent alphabet in the center. For example 6 + 4 + 4 = 14 and N is the 14th letter. Similarly 14 + 2 + 1 = 17 or the letter Q.

#449 - Fold The Cube Puzzle

Can you find out if we fold this open cube, what will be the resulting figure?

Fold The Cube Puzzle

The resulting figure will be C.

#450 - Difficult Math Trivia Question

Can you find out the remainder when 3^300 is divided by 5?

Difficult Math Trivia Question

3

It is obvious that it is not feasible to calculate 3^300 as it will take too much of time. So we will use a trick to solve the question. We will calculate the remainder of each power till we find a pattern.

3^1 divided by 5 leaves the remainder 3.
3^2 divided by 5 leaves the remainder 4.
3^3 divided by 5 leaves the remainder 2.
3^4 divided by 5 leaves the remainder 1.
3^5 divided by 5 leaves the remainder 3.
3^6 divided by 5 leaves the remainder 4.

As you can see that the pattern is now repeating itself and it will go on like this till 3^300 and beyond. Since every fourth remainder is same as the first, we will look for the power of 4 only. 300 is divisible by 4. Therefore at the power of 300, the first remainder will repeat itself and the remainder will be 3.