The following alphametic has only one solution. Can you find it?
ENLIST + SILENT + LISTEN = ANAGRAM
PS: You may start the number from 0.
Since leading a number with 0 is allowed, it can be the only possible solution:
547809 + 087549 + 780954 = 1416312
If
20 % 5 = 24
21 % 7 = 33
42 % 6 = 67
Then;
66 % 6 = ?
1211
The number on the right side is formed as (sum of digits of the 1st number)(number1/number2)
example,
20 % 5 = 24 (2+0)(20/4)
21 % 7 = 33 (2+1)(21/7)
42 % 6 = 67 (4+2)(42/6)
Simillarly,
66 % 6 = 1211 (6+6)(66/6)
Can you replace question mark to make the below equation true ?
16 ? 14 ? 4 ? 6 = 62
16 × 14 / 4 + 6 = 62
Considering below equation holds
V + II - VI = 10
IV - X + VIII = 20
IV - VII + VI = 30
Then, I + II + III = ?
60
V + II - VI = 10
=> I = 10
IV - X + VIII = 20
=> II = 20
IV - VII + VI = 30
=> III = 30
I + II + III = 10 + 20 + 30
Can you identify the logic behind the equation below and solve the puzzle by completing the equation?
12 + 13 + 7 = 1
15 + 16 + 11= 2
17 + 18 + 16 = ?
4
Logic Used: Sum the numbers and then subtract the two digits to get the desired answer.
12 + 13 + 7 => 32 => 3 - 2 => 1
15 + 16 + 11 =>42 => 4 -2 => 2
17 + 18 + 16 = 51 => 5 -1 => 4
Whats the output of below equation?
(10^0 + 10^1 *10^2 - 10^0)/10 = ?
Note: This belongs to quick-fire section riddles so you need to answer this really fast.
100
In how many ways by using number 1 to 7 and + operator, you can make the number as 100?
2 Ways
Explanation:
1 + 2 + 34 + 56 + 7 = 100.
1 + 23 + 4 + 5 + 67 = 100.
How can you make below equation true by moving one matchstick?
It can be done as explained in below picture.
Solve
6 + 7 + 8 + 9 + 11 = ?
Assuming below equations are true.
1 + 2 + 3 + 4 + 5 = 4
4 + 5 + 6 + 7 + 8 = 3
3
1 + 2 + 3 + 4 + 5 => 15 => 5 - 1 => 4
4 + 5 + 6 + 7 + 8 => 30 => 3 - 0 => 3
6 + 7 + 8 + 9 + 11 => 41 => 4- 1 => 3
Can you find values of A B And C?
0 3 A
+ A 3
=====
B B C
A = 7 , B =1 and C = 0
0 3 7
+ 7 3
=====
1 1 0