#11 - Maths Equation Operator Puzzle
I know there are two methods by using three time the same number with an plus(+) operator , you can make sum as 60.
One of them is 20+20+20.
whats the other way ?
The Other way is 55+5
I know there are two methods by using three time the same number with an plus(+) operator , you can make sum as 60.
One of them is 20+20+20.
whats the other way ?
The Other way is 55+5
Find the value of a by solving the maths equation in the picture below
2(remember bodmas)
Solve the maths equation in the picture below by placing the numbers 1 through 9 into the boxes so that all the 3 equations are correct.
There are six unique answers
Ans1:
7 x 4 = 28
36 / 4 = 9
1 + 4 = 5
Ans2:
9 x 4 = 36
28 / 4 = 7
1 + 4 = 5
Ans3:
3 x 8 = 24
56 / 8 = 7
1 + 8 = 9
Ans4:
7 x 8 = 56
24 / 8 = 3
1 + 8 = 9
Ans5:
4 x 8 = 32
56 / 8 = 7
1 + 8 = 9
Ans6:
7 x 8 = 56
32 / 8 = 4
1 + 8 = 9
We have arranged an array of numbers below. What you have to do is use any kind of mathematical symbol you know excluding any symbol that contains a number like cube root. You can use any amount of symbols but you have to come up with a valid equation for all of them.
0 0 0 = 6
1 1 1 = 6
2 + 2 + 2 = 6
3 3 3 = 6
4 4 4 = 6
5 5 5 = 6
6 6 6 = 6
7 7 7 = 6
8 8 8 = 6
9 9 9 = 6
(0! + 0! + 0!)! = 6
(1 + 1 + 1)! = 6
2 + 2 + 2 = 6
3 x 3 - 3 = 6
√4 + √4 + √4 = 6
5 + 5/5 = 6
6 + 6 - 6 = 6
7 - 7/7 = 6
8 - √√(8 + 8) = 6
√(9 x 9) - √9 = 6
Can you find out the smallest number that can be conveyed as the sum of three squares in three unique ways ?
54
7^2 + 2^2 + 1^1
6^2 + 3^2 + 3^2
2^2 + 5^2 + 5^2
In a mathematical quiz, you are asked the following question:
Use three 9's in a mathematical expression without dividing or multiplying in order to form the number one.
Can you answer the question?
The answer is 9^(9-9)
The following equation can be made correct by moving one small line. Can you find out how?
6 + 6 + 2 = 34034
Move one line from the plus sign and place it on the RHS as shown.
6 + 6 - 2 = 340/34
Below, you will find the mathematical proof that 10 equals 9.99999…. But is that possible or there is something wrong about it? Can you find the error?
x = 9.999999...
10x = 99.999999...
10x - x = 90
9x = 90
x = 10
No error is present in this proof and 10 is actually equal to 9.99999…. The proof is absolutely correct.
An equation has been laid down using a few matchsticks. However, as you can see, the equation is not correct. Can you correct the equation if you are allowed to add or remove 5 matchsticks?
Below, you can see three complete equations and one incomplete. Based on the three complete ones, can you complete the incomplete one?
5 $ 4 $ 3 $ 9 = 4215
6 $ 9 $ 2 $ 6 = 3816
4 $ 7 $ 3 $ 3 = 1122
7 $ 2 $ 7 $ 4 = ____
2418 is the answer.
The algo that has been used here is
A $ B $ C $ D = [first digit of (A * D)] [last digit of (B * C)] [first digit of (B * C)] [last digit of (A * D)]
Using the same algo,
7 $ 2 $ 7 $ 4 = [first digit of (7 * 4)] [last digit of (2 * 7)] [first digit of (2 * 7)] [last digit of (7 * 4)]
= 2418