#111 - Maths Operator Riddle
Can you get a sum of 1000 using sixteen 4s and only an addition operator
444 + 444 + 44 + 44 + 4 + 4 + 4 + 4 + 4 + 4 = 1000
Can you get a sum of 1000 using sixteen 4s and only an addition operator
444 + 444 + 44 + 44 + 4 + 4 + 4 + 4 + 4 + 4 = 1000
Replace all '*' with digits 1, 2, 3, 4, 5 and 6 to make below statement true.
* *
x *
=====
* * *
54
x3
===
162
I know a way by which i can make i can get total of 120 by using five zeros 0,0,0,0,0 and any one mathematical operator.
Do you ?
(0!+0!+0!+0!+0!)!
=(1+1+1+1+1)!
=(4)!
=5! is 5*4*3*2*1=120
Can you make numbers as 24 , using numbers 3,3,7 & 7 with any arithmetic operator ?
7 * ((3 / 7) + 3) = 24
Using Only Five 5's and any mathematical operator make sum as 37
((5!+5!)-55)/5
=>(120+120-55)/5
=>185/5
=>37
5!/(5+5)+5*5
=>120/10 + 25
=>12 + 25
=>37
I know there are two methods by using three time the same number with an plus(+) operator , you can make sum as 60.
One of them is 20+20+20.
whats the other way ?
The Other way is 55+5
Use only one mathamatical symbols and all numbers (0-9) to get sum of 99
9+8+7+65+4+3+2+1+0
Replace Question Mark With any mathamatical symbol to make statement Correct
(8 ? 0) ? (5 ? 4) ? (9 ? 5) = 3
(8 - 0) - (5 - 4) - (9 - 5) = 3
Can you arrange four 9's and use of atmost 2 math symbols , make the total be 100?
99 / .99