Hard Riddles

146900

In such cases, we calculate from the last thing. Thus in this case, let us start counting from the 9th temple. Since, he must have offered 100 coins while climbing down stairs, it means that he must have offered Rs. 100 to god on the ninth temple and offered Rs. 100 while climbing up steps. Thus it is clear that he had Rs. 300 in his pocket before climbing the steps of the 9th temple.

Similarly, we will calculate for all the temples backwards.
Before eight temple: (300+100)*2 + 100 = 900
Before seventh temple: (900+100)*2 + 100 = 2100
Before Sixth temple: (2100+100)*2 + 100 = 4300
Before fifth temple: (4300+100)*2 + 100 = 8900
Before fourth temple: (8900+100)*2 + 100 = 18100
Before third temple: (18100+100)*2 + 100 = 36,500
Before second temple: (36500+100)*2 + 100 = 73300
Before first temple: (73300+100)*2 + 100 = 146900

Therefore he had Rs. 146900 initially.

98

ab+a(a-1)
7*8+7(7-1)=56+42

Suppose you are player 1 and your friend is player 2.
You pick up 9, then your friend will choose 8.
Now you won’t be able to pick up 7 as then your sum will be more than 15 which will make you lose. But then your friend will pick 8 and will win.

Thus you will start by picking 1. If your friend picks up 2, then you will pick 3 and your friend will pick 4. Now this will force you to pick 9. The score now becomes 6 to 13 and you have no chance of winning. Thus you pick up 9 after your friend picks up 2. Then the player 2 will pick 8. The score will now be 10 to 10. Thus you pick the number 3 as picking 7 will throw him over 15. Your friend will pick 4. Now you will have no move, thus your friend will win. So it will be wise to play second.

Whenever you are drawing the balls, the number of red balls can decrease by either 2 or not decrease at all. However, in the case of blue balls, at each drawing, they can either go down by 1 or increase by 1.

Therefore, if the outset is assumed to begin with at least one ball in the urn to begin with and the number of red balls are 0 or even in number, all the red balls will finish and a blue ball will remain at the end. In the other case, one red ball will remain.

I am Mississippi.
(One Mississippi, Two Mississippi, Three Mississippi etc.)

This question can be a tricky one. The probability that is asked will be zero.

If the probability off taking out a pair of white socks is 1/2, it means that there is no black pair. This is because if there had been, there would have been three cases – white pair, black pair and mixed pair. But since in the question it is clear that there were just two chances (1/2), we can fairly deduce that there were only one black sock and the rest were white.

The fact is that both the amounts are same.
After the swap has been done, you must know that the quantity of liquid is same in both the cups as you have taken and mixed a spoonful only in both the cases. So, there is no change in the quantity of the liquids.

No if there is any tea missing from the tea cup, it is now in the coffee cup. Also, since the quantity is same, then the same amount of coffee must be missing from the coffee cup and is now in the tea cup.

You surely would not have thought that this could be that simple. It is like you are just trashing this image after thinking so much. But yeah that's how you have to do it.

This is one of the solution how you can do it. There is another way to do it. Run the horses of your mind and find out yourself.

The missing letter in the last box is Z.

Denote each alphabet to the corresponding number. For example, A = 1, B = 2, C = 3 and so on. Now you will find that the center digit is actually the product of the alphabets on both sides. In such case, the missing letter is Z.

=>G(7) * Z(26) = 182