#281 - Count Chocolates Maths Problem

A and B have a certain number of chocolates with them. If B gives one chocolate to A, they will have equal number of chocolates. But if A gives one chocolate to B, then A will be left with half the number of chocolates that B has.

Can you find out the number of chocolates they have right now?

View Answer Discuss

Let us say that A has P no. of chocolates and B has Q no. of chocolates right now.
Now according to the question:
P + 1 = Q - 1
=> Q - P = 2 ------ (i)

Also, P - 1 = (Q + 1) / 2
=> 2P - Q = 3 ------ (ii)

Equating (i) and (ii)
P = 5 and Q = 7

Therefore, A has 5 chocolates and B has 7 chocolates right now.

#282 - Hardest Counting Squares Puzzle

A network of 20 x 10 squares is given to you.

Can you calculate how many unique squares and rectangles can be formed combining two or more individual squares ?

View Answer Discuss

11550

Total number of rectangles and squares will be equal to: (Summation of row numbers) * (Summation of column numbers)
= (1 + 2 + 3 +......+ 19 + 20) * (1 + 2 + 3 +......+ 9 + 10)
= 210 * 55
= 11550

#283 - Find Number Of Days Problem

A few friends decided to go on a vacation to a resort. It was raining heavily and it kept raining for thirteen days.

When it rained in the morning, the afternoon was beautiful and when it rained in the afternoon, the day was blessed with a clear morning.

Overall, the friends experienced eleven nice mornings and twelve nice afternoons. Can you find out the number of days they spent in the vacations ?

View Answer Discuss

18

Let us solve this question by denoting variables.

Nice afternoons = P
Nice mornings = Q
No rain = R

Now, the number of days with rain = P + Q = 13
Days with clear mornings = Q + R = 11
Days with clear afternoons = P + R = 12

If we solve these three equations, we will get:
P = 7
Q = 6
R = 5

The total number of days = P + Q + R = 18

#284 - Number Guessing Riddle

Lets play a guessing game. Have selected a number in my mind and you have to find it out. The hint for you is:
The tens digit is 7 more than ones digit and the hundreds digit is 6 less than the tens digit.

Can you find the number now?

View Answer Discuss

The number that you have selected in your mind is 281.

#285 - How Many Chocolates Maths Problem

You have two jars of chocolates labelled as P and Q. If you move one chocolate from P to Q, the number of chocolates on B will become twice the number of chocolates in A. If you move one chocolate from Q to P, the number of chocolates in both the jars will become equal.

Can you find out how many chocolates are there in P and Q respectively?

View Answer Discuss

P has 5 chocolates and Q has 7 chocolates.

#286 - How Many Chocolates Maths Puzzle

In a certain offer, you can exchange 5 wrappers of chocolate to get an actual chocolate. After utilizing two weeks, a man manages to collect 77 wrappers.

Can you find out how many chocolates will he be able to get in return?

View Answer Discuss

He can get 19 chocolates.

77 wrappers will give him 15 chocolates and with 2 wrappers still left. The wrappers form the 15 chocolates he has just got combined with 2 left out wrappers will give him 3 more chocolates and 2 wrappers. The 3 wrappers from these chocolates with 2 left out wrappers will give him another chocolate.

15 + 3 + 1 = 19

#287 - Find Ages Puzzle

Aditya is 45 years older than his son Atul. If you find similarities between their ages, both of their ages contains prime numbers as the digits. Also, Aditya age is the reverse of Atul age.

Can you find their ages ?

View Answer Discuss

72,27

2, 3, 5 and 7 are the only single digit prime numbers.
Now we can list the possible combinations of age:
Aditya = 32, Atul = 23
Aditya = 52, Atul = 25
Aditya = 72, Atul = 27

Now, the third one meets our requirement.
72 - 27 = 45

Thus Aditya is 72 years old and his son is 27 years old.

#288 - Confusing Lost Chocolates Puzzle

Alex bought 150 chocolates but he misplaced some of them. His mother asked him how many chocolates were misplaced and he gave the following answer to her:
If you count in pairs, one remain
If you count in threes, two remain
If you count in fours, three remain
If you count in fives, four remain
If you count in sixes, five remain
If you count in sevens, no chocolate remain.

Can you analyze the statements and tell us how many chocolates were lost?

View Answer Discuss

119 chocolates were lost.

#289 - Distance Tyre Maths Problem

A man always keeps a spare tyre in his car. To make full use of all the five tyres, he changes the tyres in a manner that for a distance of 1, 00,000 km, each of them runs the same distance.

Can you calculate the distance traveled by each tyre in that journey ?

View Answer Discuss

80,000.

We need to calculate the 4/5th of the total distance to solve the problem.
4/5 * 1, 00,000 km = 80, 000 km

Thus, each tyre traveled 80, 000 km.

#290 - Find The Number Puzzle

There is a square of a particular number which when doubled, becomes 7 more than its quarter.

Can you find the number?

View Answer Discuss

16

Let the number be m, then the square will be m^2
According to question:
2m = (m/4) + 7
=> 8m = m + 28
=> m = 4

m^2 = 4^2 = 16.

The required square is 16.