Latest Maths Riddles

First let us assume that all other condition are fair here.
Now the toss will generate a 52:48 distribution in the favour of heads. Therefore, the toss bias factor for heads is 52/48.

In the same manner, the coin will be generating 49:51 distribution in favour of tails which makes the coin bias factor for heads in this case to be 49/51.

So, we have a combined bias factor of (52 * 49) / (51 * 48) = 2548 / 2448 which will be cancelled by a 2448 / 2548 floor factor.
The floor will be generating a distribution of 2448 / (2548 + 2448) : 2548 / (2548 + 2448) in the favour of tails which amounts to 51.00080064% tails approximately.

As per the given data,
6 * number of chocolates + 5 * number of sodas = 32

Now, we know that chocolates and sodas are definitely whole numbers; their respective values will be 2 and 4.

Aman had a 50p, a 25p and four 10p coins.

The total number of cartons required = 9.

5 cartons for large boxes = 5 * 6 = 30
4 cartons for small boxes = 4 * 9 = 36

30 + 36 = 66.

74658

* 8 + 6 =14
* 5 = 4 + 1
* 7 = 2*4 - 1
* 4 + 6 = 10
* 7+4+6+5+8 = 30

When Ramon was 14.

Thus, the answer is 31 years ago. Ramon was 14 and Athena was 42.

We know that both of them were lying in all their statements. Thus we can assume the opposite of what they said:

Priyanka: I am definitely over 30.
Rubina: I am not 28 and you are at most 4 years older to me.
Priyanka: You are at most 28.

Now we can conclude from the first statement that Priyanka is 31 years old at least. From the second and third statement, we can conclude that Rubina is at most 28 years old. Therefore, the possible ages of Priyanka and Rubina can be:

Priyanka: 31, 32, 33, 34, 35, 36...
Rubina: 22, 23, 24, 25, 26, 27...

If we look at the second statement again, we know the difference between their ages is a maximum of 4 years.
Therefore, Priyanka age is 31 years while Rubina age is 27.

If we assume that Rihana and Peeta pay the same amount, they can decide with "rock, paper, scissor" to determine who will pay the extra dollar. Any other method may be used as well. Suppose that Rihana pays $1 extra.

In this manner, Rihana pays $5, Peeta pays $4 and Logan pays $2.

If the pizza would have cost $11, this method will then prove to be great because both Rihana and Peeta will pay $5 each and Logan will pay $1. This will keep the offset same as previous. Rihana is paying 6% more, Peeta is paying 15% more and Logan is paying 27% more.

Let us denote the chocolates with a, b and c.
We can frame the following two equations now
a + b + c = 100 ------ (1)
5a + 3b + 0.5c = 100
or 10a + 6b + c = 200 ---- (2)

Now, 2*[(Eq. 2) - (Eq.1)]
9a + 5b = 100
from this equation"a" should be a multiple of 5
for a = 5 ; b = 11
for a = 10 ; b = 2
for a = 15 or more b becomes -ve

Therefore, the two possible answers are
a = 5, b = 11, c = 84
a = 10, b = 2, c = 88

There are a total of 102 animals and 34 of each kind.

Since we know that the number of each animal is equal. Therefore, each cricket, squirrel and spider will be having 18 legs.

Now, 612/18 = 34 of each animal.

Therefore, number of animals in total = 34 * 3 = 102.