#1 - JFMAMJJASON Letter Series Puzzle
What is next in this series?
JFMAMJJASON
D
Can you find the last number in the sequence below?
3 7 15 31 ?
63
Starting with 3:
3 * 2 + 1 = 7
7 * 2 + 1 = 15
15 * 2 + 1 = 31
Continuing this pattern:
31 * 2 + 1 = 63
So, using the pattern of multiplying by 2 and adding 1, the missing number in the sequence is 63.
T = 7777
R = 1111
Y = 5555
N = 4444
E = ?
E = 3333
T = 7+7+7+7 = TWENTY EIFH(T)
R = 1+1+1+1 = FOU(R)
Y = 5+5+5+5 = TWENT(Y)
N = 4+4+4+4 = SIXTEE(N)
3+3+3+3 = TWELV(E)
Continue the sequence by choosing one of the options instead of the question mark.
B.
In every line and column, there are bicycles where 2 of them are facing left, and 1 is facing right, 2 with 2 pedals, and 1 with 12 with a steering wheel and 1 without.
Can you solve the sequence?
Every segment in the new circle moves 90 degrees clockwise.
which plate should be chosen to continue the sequence?
B
every next plate makes a 1/4 turn clockwise.
which number replaces the question mark?
30
Explanation:
As you can see the lower number rows are always bigger than upper row ones with the difference going up by 3 with every step
34 - 32 = 2
32 - 27 = 5 (difference going up by 3 from last difference)
56 - 48 = 8 (difference going up by 3 from last difference)
? - 19 = 11 (difference going up by 3 from last difference)
so ? = 30
Can you find out the number that will replace the question mark?
4.
The 1st picture has 9 connecting dots / crossed lines.
The 2nd picture has one connecting dot / crossed line.
The last picture has 4 connecting dots / crossed lines.
Can you solve the below maths equation problem by replacing the question mark with the correct number?
Note: It has more than one solution.
40 or 96
Explanation:
Solution A :
Add the rhs of the last line to the current line
1 + 4 = 5
5 + 2 + 5 = 12
12 + 3 + 6 = 21
21 + 8 + 11 = 40
Solution B :
RHS = 1ST NUMBER + (1ST NUMBER * 2ND NUMBER)
1 + (1 x 4) = 5
2 + (2 x 5) = 12
3 + (3 x 6) = 21
8 + (8 x 11) = 96
Find the missing number in the table below?
89
(1st-number * 2nd-number) + (1st-number + 2nd-number) = 3rd number.
(3 x 1) + (3 + 1) = 3 + 4 => 7
(6 x 4) + (6 + 4) = 24 + 10 => 34
(8 x 7) + (8 + 7) = 56 + 15 => 71
(9 x 8) + (9 + 8) = 72 + 17 => 89 ... (Answer)