Top 5 Situation Puzzles

Robin Stole Cat
Steve stole Hen
Tim Stole Dog

Glance at the first and second statement again; they are contradictory. Both can be true together though. Also both of them cannot be false which means that Tim stole cat and his statement will be true. But it has been already deduced that the one who stole cat was telling a lie thus it can’t be possible.

Let us consider the situation again. It may be that Tim stole a hen or a dog. Assume that he stole hen. In such a case the statement of Tim will be false. But we know that the person who stole hen told the truth, thus it is contradicting our assumption and so cannot be correct.

Considering everything, now we can say with confidence that Tim stole the dog.

Now it means that the statement by Robin is completely false and the statement by Steve is true which depicts that the cat and hen are stolen by these two. Also we know that the one who stole hen is true and the one stealing cat is a liar. Thus we now know that Robin stole cat and Steve stole hen.

Falling In Love

Route66

For a change

3 minutes and 25 5/7 seconds.

The most common way how most of people see this problem is adding 3 and four to obtain 7 and they believe it should give a correct average and thus her time should be taken to 3 and half minutes. But if you do like that, you will get to a wrong answer. This is because, the wind has only helped her for three minutes while it has worked against her for four minutes.
If she could ride a mile in three minutes with the wind, it is evident that she could go a mile and 1/3 of a mile in four minutes. Thus two and 1/3 miles in eight minutes will give her actual speed as the wind has helped her as much as it has worked against her.

Thus her actual time for a single mile without wind will be 3 minutes and 25 5/7 seconds.

absolutely not

To Infinity and beyond

Assume that P is the speed of Insect X and Q is the speed of Insect Y.
Let T be the number of seconds it takes them to cross paths.
Now Distance = Speed * Time

Thus for Insect X
Distance = P * T before meeting
And Distance = P *20 after meeting

For Insect Y
Distance = Q * T before meeting
And Distance = Q * 5 after meeting

Now the distance travelled by X before meeting is equal to the distance travelled by Y after meeting and vice versa

Thus
P * T = Q * 5
And Q * T = P * 20

Solving both equations, we get T = 10

Thus Insect X requires 10 + 20 = 30 seconds,
Whereas Insect Y requires 10 + 5 = 15 seconds to change the position.

1296

(1 + (3 + 4*5)*6)*2

There can be more than one possibilities.