#581 - The Great Chocoberry Problem

Rohan, a 7 year old boy, was really fond of the chocolates called "Chocoberries". He asked his Mrs. Mother to give him some money to buy his favorite chocolates. His Mrs. Mother gave him Rs 45. He went to the shopkeeper and asked, "how much is one chocoberry for?". The shopkeeper said, Rs 3 for one chocolate. Also, if you give me the wrappers of three chocoberries, I will give you one for for the exchange.
In total, how many chocoberries could Rohan eat?

22.

He can buy 15 chocolates at first from the 45 bucks that he has. Then further, he can exchange the 15 rappers to get 5 more. Then he can return 3 rappers of the 5 to get one more chocolate, and in the end use the wrapper from this one alongwith the 2 left with him to get one more. 15+5+1+1= 22.

#582 - Create Function Puzzle

There are two variables x and y. Jimmy is required to construct a function f(a,b) which returns the maximum one in {a,b}.
You can only use +,-,ยท, / & abs() (to take the absolute value). NO if () is allowed in to jimmy.

Solve this one, math freaks.

{a+b+abs(a-b)}/2
Also, {a+b-abs(a-b)}/2 is the smaller one in {a,b}

#583 - Einsteins IQ Series

Find the next number if the sequence if you can

102 104 108 110 114 128 ?

132.

The solution lies in the fact that the series is list of sequential (prime numbers + 1) (101 103 107 109 113 127 131 being the prime numbers)

#584 - Fill The Numbers Puzzle

Given below is a figure. You have to fill in the numbers from 1 up to 16 in such a way that you get 29 when you add the numbers in each row.

Fill The Numbers Puzzle

Solution is explained in picture below

#585 - Number Of Races Puzzle

In order to complete the racing competition, the London racetrack has to submit its top and the most famous three horses to win the competition. Due to a electrical storm, all the records are cleared and no one knows which horse holds the record. They all look identical and it becomes even more difficult to differentiate the horses. There are 25 horses in the London racetrack. But there can be only five horses at a time on the track. What will the least number of races that can be conducted to find out the three fastest horses?

The numbers of races are 7.

#586 - James Bond Archer Of The Blind

James Bond is caught up in a mysterious scenario where the evil villain has him blindfolded. He somehow breaks through the handcuffs but is unable to get the blindfold off. Upon searching, he comes across a bow and 3 arrows. He can hear the villain speak, and thus tries to take a shot at him. He launches the first arrow, it misses the villain. He then launches the second arrow and it misses by a greater margin.

What is the probability that this third shot our james bond takes will be worse than the second shot?

2/3. How? Well, since he has 3 arrows, each shot has 1/3rd chance of being the best shot. So the chance that the third shot is not the best shot is 1 minus 1/3rd, thus 2/3rd.

#587 - Use Symbols Make Equation

Using the mathematical symbols like +, -, and x in order to make the equations correct. Replace @ with the above given symbols.
9 @ 8 @ 7 @ 6 @ 5 @ 4 =91

9 x 8 - 7 + 6 x 5 - 4 = 91

#588 - Crossing River Puzzle

There is a river to cross using a river raft and there are eight people (father, mother, policeman, thief, 2 daughters and 2 sons). No one knows to operate the raft except the adults and also excluding the thief. Only two people can go in the raft at a time. The raft should keep coming back and forth in order to pick and drop the people.
Rules to be followed:
Father: the father cannot stay in the raft or outside the raft without the presence of the mother.
Mother: the mother cannot stay in the raft or outside the rat without the presence of the father.
Thief: the thief is not allowed to stay with any of the family member unless there is a policeman.
Policeman: the policeman can travel with anyone.
2 sons and 2 daughters: they are not allowed to travel in the raft without the presence of any adult. They cannot either travel in the presence of only thief without the policeman. The sons cannot be with their mothers without their fathers supervision. The daughters are not allowed to be there with their fathers without the supervision of their mothers. But the daughters and the sons can be left unsupervised (as long as the other rules are applied).
What is the sequence that the people should follow in order to cross the river through the raft keeping in mind all the rules?
The rules are applicable not only in the raft but also outside the raft.

The following letters are assigned to respective person. Father (F), mother (M), thief (t), policeman (p), sons (s1 & s2), daughters (d1 &d2). And imagine that they are starting from the eastern side of the river |.
During the first trip, t will be taken across the river by P. The rules are still kept. After leaving t, P will return. So now it is t | P, M, d1, d2, s1, s2, F
In the second trip, d1 will be taken by P across the river and leave her back. But t will be brought back. Now it is d1 | P, F, M, d2, s1, s2, t
During the third trip, d2 will be taken across the river by M and will return. Now it is d1, d2 |P, M, F, t, s1, s2
In the fourth trip, F and M will cross the river together and M will stay back and F will return. Now it is M, d1, d2 |P, F, t, s1, s2
During the fifth trip, t will be taken across the river by P and M will return. So now it is P, d1, d2, t |M, F, s1, s2
In the sixth trip, F and M will go across the river and F will be back. Now it is P, M, d1, d2, t |F, s1, s2
During the seventh trip, s1 will be taken across the river by F and P will come back with t. now it is M, F, d1, d2, s1 |P, t, s2
In the eighth trip, s2 will be taken across the river by P, and then he will return. Now it is M, F, d1, d2, s1, s2 |P, t
In the ninth trip which is final t will be taken across by P.
This is by the assumption that the thief is left unsupervised. The rules do not mention that anyway.

#589 - Who Am I Size Shape

I am a curved, sometimes I am straight. I come in different shapes and sizes. You can fit me anywhere, but in the end, there is only one right place for me.

What am I ?

A jigsaw Puzzle Piece.

#590 - Find Number Problem

Find out a number which is less than 100 and is more than one fifth of its actual value when the digits are reversed.

The number is 45
1/5 of 45 = 9
9+45 is 54.