You board a train. The train will have to enter a tunnel soon. You are claustrophobic. Which place is the best for you to sit ?
The back seat of the last coach will be the best. The reason is because, the train will be accelerating after the stop and thus, it will be much faster when the back of the train enters the tunnel than when the front of the train enters. Thus you will have to spend less time in the tunnel.
Given the numbers between 1 and 1 million, what is so special about the number 40 that it makes the number stand out of the crowd ?
The number 40 (Forty) is the only number which when written in English has all the letters in the same order as in the alphabets.
If you remove one from eleven, it becomes ten. If you remove one from nine, it becomes ten.
How is this possible ?
It is possible if you are using Roman Numerals.
9 = IX
10 = X
11 = XI
Now it is all possible.
A devotee visits 9 temples when he visits India. All these nine temples have one thing in common - there are 100 steps in every temple. The devotee puts Re.1 coin after climbing up every step. He does the same while climbing down every step. At each temple, the devotee offers half of his money from his pocket to god. In this way, his pocket becomes empty after his visit to 9th temple.
Can you calculate the total amount he had initially ?
146900
In such cases, we calculate from the last thing. Thus in this case, let us start counting from the 9th temple. Since, he must have offered 100 coins while climbing down stairs, it means that he must have offered Rs. 100 to god on the ninth temple and offered Rs. 100 while climbing up steps. Thus it is clear that he had Rs. 300 in his pocket before climbing the steps of the 9th temple.
Similarly, we will calculate for all the temples backwards.
Before eight temple: (300+100)*2 + 100 = 900
Before seventh temple: (900+100)*2 + 100 = 2100
Before Sixth temple: (2100+100)*2 + 100 = 4300
Before fifth temple: (4300+100)*2 + 100 = 8900
Before fourth temple: (8900+100)*2 + 100 = 18100
Before third temple: (18100+100)*2 + 100 = 36,500
Before second temple: (36500+100)*2 + 100 = 73300
Before first temple: (73300+100)*2 + 100 = 146900
Therefore he had Rs. 146900 initially.
Can you find out the number of the parking space in which the car is parked?
The parking number is 87. You will know why if you invert the image and then see.
Complete the picture sequence ?
98
ab+a(a-1)
7*8+7(7-1)=56+42
You are playing a game with your friend Jack. There are digits from 1 to 9. You both will take turn erasing one digit and adding it to your score. The first one to score 15 points will win the game.
Would you want to play first or second?
PS: The sum should be exactly 15.
Suppose you are player 1 and your friend is player 2.
You pick up 9, then your friend will choose 8.
Now you won’t be able to pick up 7 as then your sum will be more than 15 which will make you lose. But then your friend will pick 8 and will win.
Thus you will start by picking 1. If your friend picks up 2, then you will pick 3 and your friend will pick 4. Now this will force you to pick 9. The score now becomes 6 to 13 and you have no chance of winning. Thus you pick up 9 after your friend picks up 2. Then the player 2 will pick 8. The score will now be 10 to 10. Thus you pick the number 3 as picking 7 will throw him over 15. Your friend will pick 4. Now you will have no move, thus your friend will win. So it will be wise to play second.
In the given figure, you can see that four match sticks are used to form a square. Can you form five squares by using six matches?
Simple answer :=)
There are a certain number of blue balls and a certain number of red balls in an urn. You pick up two balls from the urn randomly. If you find that they are opposite in colors, you throw them and put a red ball in the urn. If they are of same colors, you throw them and put a blue ball in the urn.
Thus you are reducing the number of balls in the urn one at a time no matter what the case is. After going through it again and again. Only one ball will be remaining in the end. If you are told the respective number of blue and red balls at the outset, will you be able to predict the color of the final ball ?
Whenever you are drawing the balls, the number of red balls can decrease by either 2 or not decrease at all. However, in the case of blue balls, at each drawing, they can either go down by 1 or increase by 1.
Therefore, if the outset is assumed to begin with at least one ball in the urn to begin with and the number of red balls are 0 or even in number, all the red balls will finish and a blue ball will remain at the end. In the other case, one red ball will remain.
Ten coins have been arranged as you can see in the given picture. In this arrangement, a triangle is formed pointing upwards. You have to invert the position of the triangle and make it point downwards while just changing the position of 3 coins only.Can you do it?
See the picture given. It is self-explanatory. Just move the coins as shown and you will get the desired result.