#221 - Logic Dice Riddle

A solo dice game is played. In this game, upon each turn, a normal pair of dice is rolled and the score is calculated not by adding the numbers but multiplying them.

It is observed that in a particular game, the score for the second roll is five more than what was achieved in the first roll. The score for the third roll is six less than what was achieved in the second roll. The score for the fourth roll is eleven more than what was achieved in the third roll. The score for the fifth roll is eight less than what was achieved in the fourth roll.

Can you calculate the score for each of the five throws ?

Logic Dice Riddle

Score for the first roll - 10
Score for the first roll - 15
Score for the first roll - 9
Score for the first roll - 20
Score for the first roll - 12

#222 - Fun Equation Puzzle

You are given the sum of symbols in each row and column in the attached figure. Analyzing the figure, can you find out the value of the symbols?

Fun Equation Puzzle

Value of Circle is 3
Value of Star is 5
Value of Triangle is 4

#223 - Mathematical Proof Puzzle

Below, you will find the mathematical proof that 10 equals 9.99999…. But is that possible or there is something wrong about it? Can you find the error?

x = 9.999999...
10x = 99.999999...
10x - x = 90
9x = 90
x = 10

Mathematical Proof Puzzle

No error is present in this proof and 10 is actually equal to 9.99999…. The proof is absolutely correct.

#224 - Challenging Math Problem

You have $100 with you and you have to buy 100 balls with it. 100 is the exact figure and you cant go below or above the numbers and you have to use the entire $100. If there is no kind of tax applied how many of each of the following balls will you be able to buy:

Green Balls costing $6
Yellow Balls costing $3
Black Balls costing $0.10

Now, how many of each must you buy to fulfill the condition given?

1 green ball = $6
29 yellow balls = $87
70 black balls = $7

Detailed Explanation :
Let us denote the number of balls to be brought with a variable
p = green sponges
q = yellow sponges
r = black sponges

Now using a simple expression:
p + q + r = 100
6p + 3q + 0.1r = 100

Multiplying the first equation by 6 then 3 and subtracting the two equations, we get:

6p + 6q + 6r = 600
3p + 3q + 3r = 300

3q = 500 - 5.9r
3p = 2.9r - 200

Usually, we have three equations to solve three variables. However, we will manage with just two here because we know that p and q are non-negative integers.
If 3q >/= 0, then 500 - 5.9r >/= 0.
Using this, r Also, if 3p >/= 0, then 2.9r - 200 > 0. This implies that r >/= 68.97.

Now, the number of black balls must be an even dollar amount or we will land up with a fraction. Considering the expressions, you know that there can be just two integers that can satisfy the condition while lying in between 68.97 and 84.75.

If we take r as 80 and solve the equations (the last two equations), we will get p = 10.67 and q = 9.33. But p and q must be integer and not fraction. Thus you can cancel out 80.

If we take r as 70, we will get p = 1 and b = 29.

Therefore following are the number of balls that we must buy:
1 green ball = $6
29 yellow balls = $87
70 black balls = $7

#225 - Murder Mystery Logic Puzzle

A man is approaching a broad and barren land. He has a package with him. If somehow, he is unable to open the package before reaching the land, he will die.

Can you guess what is present in the package?

Murder Mystery Logic Puzzle

The package contains a parachute and he has doing air diving.

#226 - Can You Answer This mystery Riddle

A Japanese ship was en route to a mission in foreign seas. The captain of the ship felt tired and thought of taking a bath. He went for taking the shower and removed his diamond ring and Rolex and kept them on the table. When he returned after taking the bath, he found that the ring and watch were stolen.

He called the five members of the crew whom he suspected and asked them what they were doing for the last 15 minutes.
The Italian cook (with a butcher knife in hand): I was in fridge room getting meat for cooking.
The British Engineer (with a high beam torch in hand): I was working on generator engine.
The Pakistani seaman: I was on the mast correcting the flag which was upside down by mistake.
The Indian Radio officer: I was trying to make a contact with the company to inform them about our position.
The American navigation officer: I am on night watch, so I was sleeping in my cabin.

Upon listening to them, the captain caught the lying member. Who do you think stole the valuables?

Can You Answer This mystery Riddle

The Pakistani seaman is lying. This is because the Japanese flag looks the same upside down. There was no need to correct it and thus he is plainly lying.

#227 - Logic Birthday Problem

I engaged in a strange activity. My birthday was approaching and I decided to collect money for my birthday bash. On the first day of the month, I kept a dollar in my piggy bank, on the second, I kept two dollars and on the third, I kept three and so on.

On my birthday, I had a total of 276 dollars in my piggy bank. Can you find out on which day of the month was my birthday?

Logic Birthday Problem

23rd

The easiest way to find out without engaging in any formula would be to simply add them:
1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 + 21 + 22 + 23 = 276

Thus, the birthday falls on the 23rd day of the month.

#228 - Match Stick Puzzle

In the given picture, you can find five identical squares. You have to form six identical squares by moving just three matchsticks. How will you achieve it if you are not allowed overlapping or breaking of matchsticks?

Match Stick Puzzle

As you can see in the picture, we have lifted the bottom three matches and placed them inside the middle squares vertically (pink ones). We now have six identical squares.

#229 - Awesome Optical Illusion Picture Puzzle

This black and white picture shows a couple by the lakeside. The picture is quite serene. But can you find out something in this picture that does not meet the eyes?

Awesome Optical Illusion Picture Puzzle

If you would have concentrated over the branches of the tree, you would have found out. It is a baby face. We have highlighted the picture for you.

#230 - Tricky Cryptogram Puzzle

Below, you can see some coding:
January = 1017
February = 628
March = 1335
April = 145
May = 1353
June = 1064
July = 1074
August = 186

Now deciphering the way it has been coded, can you find out how September will be coded?

January = 10|1|7
10 is the position of letter J in alphabetical order.
1 is the position of January in months.
7 is the number of letters used in the word January.

Same goes for all the months, thus
September = 19|9|9 (1999).