#161 - Maths Equation Puzzle With Twist

2 - 2 = 00
3 - 3 = 03
4 - 4 = 08
5 - 5 = 15
6 - 6 = 24
7 - 7 = ??

Maths Equation Puzzle With Twist

35

The value of RHS is
(A*A) - (A+A)

i.e
(2*2) - (2+2) = 4 - 4 = 00
(3*3) - (3+3) = 9 - 6 = 03
(4*4) - (4+4) = 16 - 8 = 08
(5*5) - (5+5) = 25 - 10 = 15
(6*6) - (6+6) = 36 - 12 = 24
(7*7) - (7+7) = 49 - 14 = 35

#162 - 8 + 8 / 2(1+3) Viral Maths Puzzle

Can you solve the below viral equation?

8 + 8 / 2(1+3)= ?

90% Failed to solve the above equation.

8 + 8 / 2(1+3) Viral Maths Puzzle

24

8 + 8 / 2(1+3)= ?
8 + 8 / 2(4)= ?
8 + 4(4)= ?
8 + 16 = ?
24

#163 - Two Dog And Bones Maths Algebraic Puzzle

Can you solve the below viral Maths Equation?

Two Dog And Bones Maths Algebraic Puzzle

14

#164 - Good Halloween Equation Brain Teaser

Can you solve the below Halloween Equation?

Good Halloween Equation Brain Teaser

95

#165 - Answer Fast Maths Equation Brain Teaser

Can you solve the below quickfire equation?

Answer Fast Maths Equation Brain Teaser

1 or -1

#166 - Men Disc and Headphone Equation Puzzle

Can you solve the below Men Disc and Headphone equation?

Men Disc and Headphone Equation Puzzle

43

#167 - 6 + (-1^2)^3 x 4 / 2 Maths Equation

Can you solve the below Maths Equation?

6 + (-1^2)^3 x 4 / 2 Maths Equation

4

#168 - Burger Drink Fires Maths Problem

Can you solve the below KFC equation to prove that you are really smart?

Burger Drink Fires Maths Problem

15

#169 - Competitive Exams Hard BODMAS Question

Can you solve the below equation?

30 / 6 * 2 - 3 * 2 + 12 / 2 = ?

Competitive Exams Hard BODMAS Question

10

#170 - Garden Chase Puzzle

In a rectangular garden, a sneaky snake is slithering swiftly along the length. Simultaneously, a determined man begins his pursuit from one end of the breadth. The snake moves at a steady pace of 30 cm/hour, while the man walks twice as fast, covering 60 cm/hour.

The question is, how long will it take for the man to catch up to the snake?

Garden Chase Puzzle

Consider the garden's breadth as "B" and its length as "2B." The man and snake start moving at the same time.

To find the time "T" when the man catches the snake, we equate the distances they both cover.

Man's distance: 60T (60 cm/hour * T hours)
Snake's distance: 30T (30 cm/hour * T hours)

The man catches the snake when they meet at the same point, meaning the distance covered by both is equal.

Equation: 60T = 30T

Solving for "T":
60T - 30T = 0
30T = 0
T = 2

Thus, the man catches the snake after 2 hours.