Which pattern is the odd one out?
Shape A
Shape A features an inner figure(dark black) in the form of a trapezoid.
Conversely, shapes B, C, and D all exhibit an inner figure shaped as a triangle.
As a result, the image that deviates from this pattern is Shape A, making it the odd one out.
If 8/x = 160, what is the value of x?
a) 20
b) 1280
c) .05
d) 1/2
.05
Given the equation 8/x = 160, when you solve for x, you indeed get:
8/x = 160
To find x, you can simply invert the fraction:
x/8 = 1/160
Now, to isolate x, multiply both sides by 8:
x = 8 * (1/160)
x = 8/160
x = 1/20 = 0.05
1f
1 = 02
2 = 10
3 = 30
4 = 68
Then
5 = ?
130
Explanation:
(1*1*1)+1 = 02
(2*2*2)+2 = 10
(3*3*3)+3 = 30
(4*4*4)+4 = 68
(5*5*5)+5 = 130
Sonal asked the class to see if they could find the sum of the first 50 odd numbers. As everyone settled down to their addition, Lavesh ran to her and said, 'The sum is 2,500.' Ms. Sonal thought, 'Lucky guess,' and gave him the task of finding the sum of the first 75 odd numbers. Within 20 seconds, Lavesh was back with the correct answer
How does Lavesh find the sum so quickly and what is the answer ??
The following pattern holds: The sum is equal to n x n, when n is the number of consecutive odd numbers, starting with 1. For example, the sum of the first 3 odd numbers is equal to 3 x 3, or 9; the sum of the first 4 odd numbers is equal to 4 x 4, or 16; the sum of the first 5 odd numbers is equal to 5 x 5, or 25; and so on.
Many people would think Friday the 13th will be an unlucky day. Is it possible that there is no Friday on 13th through the whole year? How many Fridays at 13th can we have in a year at most? Can you calculate it out?
We can calculate out how many days there will be for the 13th on each month if we count from the beginning of the year (January 1). Then we divide total days by 7 to get the remainders. We also need to consider the leap year. Through the whole year we had all kinds of remainders, from 0 to 6. The minimum of occurence for all the unique remainders was 1. It means that we have at least one Friday on 13th. In a regular year, the best chance you can get 3 Fridays on 13th, which are in February, March and December because the remainders of these 3 months are 2. In a leap year, the best chance you also can get 3 Fridays on 13th, which are in January, April and July because the remainders of these 3 months are 6.
Replace the 'X' by any mathematical symbol to make the expression equal to 99.
18 X 12 X 2 X 3 = 111
18 x 12 ÷ 2 + 3 = 111
A number with an interesting property:
When I divide it by 2, the remainder is 1.
When I divide it by 3, the remainder is 2.
When I divide it by 4, the remainder is 3.
When I divide it by 5, the remainder is 4.
When I divide it by 6, the remainder is 5.
When I divide it by 7, the remainder is 6.
When I divide it by 8, the remainder is 7.
When I divide it by 9, the remainder is 8.
When I divide it by 10, the remainder is 9.
It's not a small number, but it's not really big, either.
When I looked for a smaller number with this property I couldn't find one.
Can you find it?
The number has to end in 9.
Looked brute force for small numbers.
59 and 119 were promising, but no cigar.
Then looked for agreement among
39 + multiples of 40,
69 + multiples of 70 and
89 + multiples of 90
Smallest one was 2519.
5+3+2 = 151022
9+2+4 = 183652
8+6+3 = 482466
5+4+5 = 202541
THEN ;
7+2+5 =
7*2 , 7*5 , 7*2 + 7*5 -2
The puzzle is if the shopkeeper can only place the weights in one side of the common balance. For example if shopkeeper has weights 1 and 3 then he can measure 1, 3 and 4 only. Now the question is how many minimum weights and names the weights you will need to measure all weights from 1 to 1000. This is a fairly simple problem and very easy to prove also. Answer for this puzzle is given below.
This is simply the numbers 2^0,2^1,2^2 ... that is 1,2,4,8,16... So for making 1000 kg we need up to 1, 2, 4, 8, 16, 32, 64, 128, and 512
An express train takes 3 seconds to enter tunnel which is 1 km long.
If it is traveling at 120 km an hour, how long will it take to pass completely through the tunnel
The train takes 30 seconds to travel 1 km, plus 3 seconds for the complete train to pass any point, making a total of 33 seconds.